问题描述: 已知tan(a+β)=7,tana*tanβ=2/3则cos(a-β)= 1个回答 分类:数学 2014-11-22 问题解答: 我来补答 tan(a+β)=7(tana+tanβ)/(1-tanatanβ) = 73(tana+tanβ) = 73sin(a+β)/cosacosβ = 7cosacosβ= 3sin(a+β)/7= 3(7/5√2)/7= 3/(5√2) = 3√2/10 tanatanβ = 2/3sinasinβ/cosacosβ = 2/3sinasinβ = (2/3)cosacosβ = (2/3)(3√2/10)= √2/5cos(a-β) =cosacosβ+ sinasinβ = 3√2/10 + √2/5= √2/2 展开全文阅读