1/2×4+1/3×5+.1/（n+1)(n+3)等于?1+2/3+3/3².+n/3的n-1次方 等于?

1/(n+1)(n+3)=[1/(n+1)-1/(n+3)]/2
1/2×4+1/3×5+.1/（n+1)(n+3)
=(1/2)*(1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7+...+1/(n+1)-1/(n+3))
=(1/2)*(1/2+1/3-1/(n+2)-1/(n+3))
=(1/2)*(5/6-1/(n+2)-1/(n+3))
Sn= 1+2/3+3/3^2+...+(n-1)/3^(n-2)+n/3^(n-1)
3Sn=3+2+3/3+4/3^2+...+n/3^(n-2)
2Sn=3+[1+1/3+1/3^2+...+1/3^(n-2)]-n/3^(n-1)
=3-n/3^(n-1)+[1-(1/3)^(n-1)]/(1-1/3)
=3-n*3^(1-n)+3/2-(3/2)*3^(1-n)
=9/2-(n+3/2)*3^(1-n)