函数y=［log(1/3)x+2］∧0的定义域是?

y=[log(1/3) x+2]^0
首先,log(1/3) x+2≠0
log(1/3) x≠-2
x≠(1/3)^(-2)
x≠9
其次,真数x>0
定义域：(0,9)U(9,+∞)