(1/11+1/20+1/31+1/40)*(1/21+1/30+1/41+1/50)-(1/11+1/21+1/31+

问题描述:

(1/11+1/20+1/31+1/40)*(1/21+1/30+1/41+1/50)-(1/11+1/21+1/31+1/41+1/51)*(1/21+1/31+1/41)=?
1个回答 分类:数学 2014-11-12

问题解答:

我来补答
题目错了吧?
题目是不是这样的:
(1/11+1/21+1/31+1/41)*(1/21+1/31+1/41+1/51)-(1/11+1/21+1/31+1/41+1/51)*(1/21+1/31+1/41)
令a=1/21+1/31+1/41
∴原式=(1/11+a)*(a+1/51)-(1/11+a+1/51)*a
=a/11+a²+1/11*51+a/51-a/11-a²-a/51
=1/561
 
 
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