问题描述: x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4如何分解因式 1个回答 分类:数学 2014-09-23 问题解答: 我来补答 原式=(x+2)/(x+1)-(x+3)/(x+2)-(x-4)/(x-3)+(x-5)/(x-4)=[(x+2)*(x+2)-(x+3)*(x+1)]/(x+1)*(x+2)--[(x-4)*(x-4)-(x-3)*(x-5)]/(x-3)*(x-4)=1/(x+1)*(x+2)-1/(x-3)*(x-4)=[(x-3)*(x-4)-(x+1)*(x+2)]/[(x+1)*(x+2)*(x-3)*(x-4)]=10(1-x)/[(x+1)*(x+2)*(x-3)*(x-4)] 展开全文阅读