问题描述: 已知{(x²+y²)-(x-y)²+2y(x-y)}÷4y=1,求4x²-y²分之4x -- 2x+y分之1 的值! 1个回答 分类:数学 2014-10-30 问题解答: 我来补答 {(x²+y²)-(x-y)²+2y(x-y)}÷4y=1{x²+y²-(x²-2xy+y²)+2xy-2y²}÷4y=1{x²+y²-x²+2xy-y²+2xy-2y²}÷4y=1{4xy-2y²}÷4y=12y{2x-y}÷4y=1{2x-y}÷2=12x-y=24x/(4x²-y²)-1/(2x+y)=4x/[(2x-y)(2x+y)]-(2x-y)/[(2x-y)(2x+y)]=[4x-(2x-y)]/[(2x-y)(2x+y)]=(4x-2x+y)/[(2x-y)(2x+y)]=(2x+y)/[(2x-y)(2x+y)]=1/(2x-y)=1/2 展开全文阅读