先化简在求值[(ab+ac)²+(ab-ac)²][(b+c)²-(b-c)²]

问题描述:

先化简在求值[(ab+ac)²+(ab-ac)²][(b+c)²-(b-c)²]÷4abc
a=8,b=-1/2,c=1/4
1个回答 分类:数学 2014-11-18

问题解答:

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[(ab+ac)²+(ab-ac)²][(b+c)²-(b-c)²]÷4abc
=[(ab)²+2a²bc+(ac)²+(ab)²-2a²bc+(ac)²][b²+2bc+c²-b²+2bc-c²]÷4abc
=2[(ab)²+(ac)²]4bc÷4abc
=2[(ab)²+(ac)²]÷a
=2a[b²+c²]
 
 
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